2. Theoretical methodThe BTHG of helium atom in the laser field can be obtained by solving the TDSE of He atom with a single-electron approximation. In the length gauge, the TDSE of He atom in dipole approximation can be written as (atomic units are used, unless otherwise stated)
where
H0 is the field-free Hamiltonian of a He atom:
here,
is the spherical harmonic function,
Vl is the angular momentum-dependent model potential of He atom
[19]where
α is the dipole polarization rate of He
+ ion,
rc,
A1,
A2,
B1, and
B2 can be found in Ref. [
20],
is a truncation function, which can be expressed as:
is the interaction between He atom and laser field, which can be written as
where
E0,
ω,
are the electric field amplitude, the angular frequency, and the envelope of the laser pulse, respectively.
The time-dependent generalized pseudo-spectral (short as TDGPS) method[21] is used to solve the TDSE (1) in spherical coordinates accurately. This method takes the non-uniform optimal spatial discretization of the coordinates. The time propagation of the wave function under this method is performed by the split operator method as follows:
Once obtaining the time-dependent wave function of the interaction between atom and laser field, we can calculate the expectation value of the induced dipole moment in the length form:
The HHG power spectra in the length form can be obtained using the Fourier transformation of the time-dependent dipole moment
:
To understand the dynamic process of the HHG, we perform the time-frequency analysis by means of the synchrosqueezing transform (SST).[11] Compared with traditional TF techniques, such as Gabor transform, Morlet transform, etc., the SST can resolve the intrinsic blurring in the TF spectra below the ionization threshold and produce a clear spectrum.
3. Results and analysisBy using the method mentioned above, we have calculated the BTHG of He atom in the laser field when the initial state of the atom is in the ground state. In our calculation, we choose a laser electric field with a 34-cycles and
envelope. In Fig. 1, we show the calculated BTHG of He atom for the driving wavelength 335 nm at the intensities I = 1.0 ×1014 W/cm2, I = 1.5 ×1014 W/cm2, and I = 2.0 ×1014 W/cm2, and for the driving wavelength 200 nm, 335 nm, and 470 nm in the driving intensity I = 2.0 ×1014 W/cm2, respectively.
In Fig. 1(a), the unusual harmonic peaks (satellite-peaks) appear at the left side of the normal 3rd order to the 9th order, and the peaks become stronger and have a shift with the laser intensities, and the peaks disappear at 200-nm and 470-nm wavelengths [see Fig. 1(b)]. The results for He atom are similar to that of hydrogen atom in Ref. [15]. The satellite-peaks for hydrogen atom are attributed to the transition between the pre-excited bound states to ground state.[15] They identified the satellite-peaks of the 5th and 7th orders as the 2p–1s and 3p–1s transitions, respectively. However, the satellite-peaks of the 5th (or 3rd) order of He atom cannot produce from the transition between the excited states and the ground state because the energy level differences between the excited states to the ground state, which is larger than the energy location of the peak, even between the first excited state and the ground state. In order to confirm the origin of the satellite-peaks of the BTHG, we perform the time-frequency (TF) analysis by means of SST method for the BTHG at driving intensity I = 2.0×1014 W/cm2 with a 335-nm wavelength, as shown in Fig. 2. The satellite-peaks of the 3rd, 5th, and 9th orders are mainly emitted on the falling edge of the laser pulse as shown in Fig. 2(a). This is consistent with the e-HHG results reported in Ref. [13]. Namely, the e-HHG attributed to the ionization of the pre-excited states, then recombination to the ground state of Ar atom. However, here the emission characteristics of the satellite-peaks of the 3rd, 5th, and 9th orders of He atom are different from that of Ar atom because the energy locations of the satellite-peaks for He atom are lower than the transition energy. In the case of He atom, the satellite-peaks of the 3rd, 5th, and 9th orders emit only in the falling edge of the laser pulse, while the satellite-peaks of the 7th order does not only emit on the falling edge, but also after the laser end. This indicates that the side peak of the 7th order emission differs from the other peaks. The fact that the emission occurs after the laser suggest a part of the satellite-peaks of the 7th order coming from the transition between the field-free excited state to the ground state. Because the life of the atomic excited state is nanosecond scale in general, and the width of laser pulse is in femtosecond level, therefore, in the excited-state atom after laser propagation, within the scope of the nanosecond order of magnitude, there is still a radiation. We can identify it belong which the transition based on the position of the satellite-peaks. The lowest excited state for the allowed transition to the ground state of He atom is 2p,
a.u., a photon energy for 335 nm is 0.136 a.u.,
. Obviously, the satellite-peaks corresponding to transition from 2p state to the ground state should be near the 6th order, but satellite-peaks of emission appear at 6.1 and 6.4 orders at the end of the laser field.
Next, we will recognize the contributions of excited states to the satellite-peaks of left-side of the 7th order near the end of the laser field. In Fig. 2(b), at the end of the laser pulse, the satellite-peaks near the 7th order locates at 6.1ω and 6.4
. For the transition between 4p, 3p, and 1s states, the energy differences
,
are 6.4ω and 6.3ω, respectively. Therefore, we speculate that the 4p and 3p states have a certain number of populations when the laser pulse is over, which leads to the emission caused by the transition from 4p (3p) to 1s state. To confirm this result, we can project the time-dependent wave function on the 4p, 3p, and 2p states during near the end of the falling edge of the laser pulse. We find that the population of 4p and 3p state is larger than 2p state case, as shown in Fig. 6(a). As the analysis above, the satellite-peaks of the 7th order in Fig. 2(b) are composed of two parts. One part can be attributed to the transition between the 4p, 3p, and 1s states in the field free, and the other part comes from the transient Stark shift of the 4p, 3p states in the laser field. The satellite-peaks of the 3rd, 5th, and 9th orders are only generated by the transition between the dressed states. Furthermore, we find that the difference between the peak position of these satellite-peaks is approximately 2ω. This indicates that the satellite- peaks of the new set of harmonics have a energy relationship with new energy levels. To explain this, we consider the energy relation of the BTHG to the atomic dress states in the laser field. We defined that the transient Stark shift of the bound state is Ux at time t, the emission energy of the satellite-peaks for the BTHG can be given by
| |
where
, and
are the energy levels of the zero order dress states of the excited state
jp, and the ground state 1s of atom in the laser field, respectively,
[22] q is a non-integer,
is the energy of a photon in the satellite-peaks. The energy levels for the dress states of 3p and 1s of He are shown in Fig.
3. From the result shown, we can easily explain the reason that the interval between the adjacent satellite-peaks is 2
ω.
According to multi-photon process, the BTHG is the result of the transition between the dressed states formed by the same state in field-free (not shown in Fig. 3). Here, we can understand for the satellite-peaks of the BTHG as the transition between the dressed states formed by some different states with field-free. The corresponding transitions for the satellite-peaks are shown schematically in Fig. 3. For example, the transition 1 in the figure corresponds to the satellite-peaks of the 7th order, the transition 2 emits the satellite-peaks of the 5th order, and the transition 3 gives the satellite-peaks of the 3rd, even it is weak. We find that the adjacent interval of the satellite-peaks is 2ω. Figure 3 shows an instantaneous transition diagram for the satellite-peaks. In fact, the radiation energy will change with time propagation, but the energy difference of the radiation at any time is always 2ω, as shown in Fig. 2 (also seen in Fig. 4). Because the transition for the satellite-peaks shown in Fig. 2 involves the dressed states of 3p, 4p states, the shape of the SST figure is complex. If only a single excited state is involved, we can use the SST diagram to calculate the instantaneous stark shift Ux of the atomic excited state at a given time,
called the instantaneous stark shift of the excited state.
To study the characteristics of the satellite-peaks of the BTHG when only one excited state has a distinct population, for example, 2p state, we calculated the low-order harmonics of He atom driven by a laser pulse with the wavelength 470 nm and intensity I = 1.4×1014 W/cm2, and the corresponding time-frequency analysis (SST). Our results are shown in Fig. 4. we can see that only the satellite-peaks near the 8th order emits at the end of laser pulse, which indicates that the emission is due to the result of the transition between the excited state and the ground state in field-free. Next, we will analyze this process according to Eq. (9) combined with Fig. 4(b). We can estimate the instantaneous Stark shift value if any harmonic energy of the satellite-peaks at any time is chosen. For example, if
, then according to Eq. (9), we can get
, the corresponding transition is the process 1 in Fig. 3 (but 3p is replaced by 2p in the figure). If
, due to
a.u. according to Eq. (9), then
a.u., which is very close to Up (Up is ponderomotive energy, here
a.u.). That explains very well the reason that the energy difference between the satellite-peaks and the 9th order is
. It also suggests that the biggest Stark shift for the 2p state of He atom in laser field just is the difference, i.e.,
.
For the satellite-peaks of the 7th order, although the side peak does not appear in Fig. 4(a), there is a red shift for the order, which is the combined contribution of the normal HHG and transition of the dressed states shown in SST analysis (Fig. 4(b)). For the side peak of the 11th order, it can be understood as the transition from
to
in Fig. 3 (note: 3p is replaced by 2p in the figure). That is the reason for the interval of the satellite-peaks is 2ω.
If we choose the laser wavelength is 425 nm, intensity is 1.4×1014 W/cm2, we calculated the BTHG of He atom. The results are shown in Fig. 5. From the figure, we can find some satellite-peaks still appear. In the SST analysis, a satellite-peaks of the 9th order is still emission even at the end of the laser pulse, and the main contribution of the satellite-peaks comes from the emission. We can calculate
, so the emission should be the transition from the 4p excited state to the ground state in field-free, which means a certain number of population in 4p state at the end of laser pulse. Based on the difference between the satellite-peaks and main peak of the 9th order, we can estimate the difference is
a.u., and by calculating the
a.u. both results are almost the same, which indicates the maximum Stark shift of the excited state 4p of He atom in laser field is
,
, the energy difference between the side peak and the main peak of the 9th order just is the maximum Stark shift.
It should be pointed out that the position of the satellite-peaks of the BTHG would change with the laser intensity when the satellite-peak emission only comes from the transition between the dressed states in laser field. And when the satellite-peak emission originated from two kinds of transition, i.e., the transition between the dressed states in laser field and the excited state to ground state in field-free, for the part of the transition between the excited state to ground states in the field-free, the position of the satellite-peaks is independent of the laser intensity. If the contribution of the transition between the dressed states is dominant, the position of the satellite-peak will still change with the laser intensity (as shown in Fig. 1(a)). Hence, when the contribution of the satellite-peaks of BTGH from the excited state to ground state in field-free is dominant, the energy difference between the satellite-peak and the main peak can be used to determine the Stark shift of the excited state of He atom.
For the analysis of the side peaks above is based on the energy relation of atomic energy levels and Stark shift, which include the transition of 4p–1s or 3p-1s (Fig. 2) and 2p–1s (Fig. 4). We can also confirm the transitions near the end of laser pulse mentioned above occur by the electron population in 2p, 3p, and 4p states of He atom driven by the laser intensity 2.0×1014 W/cm2 with wavelength 335 nm, and intensity 1.4×1014 W/cm2 with wavelength 470 nm and 425 nm, respectively. The results are shown in Fig. 6.
In the first case (Fig. 6(a)), the populations on the excited states 4p and 3p are much higher than that of 2p state after the 16th cycle. The population of 2p state is almost zero after 17 cycles, and the population on 4p state is higher than 3p. Therefore, that is the reason that emission probability for 4p–1s transition is much stronger than that of 3p–1s transition at the end of the laser in the time-frequency analysis diagram of Fig. 2; In the second case (Fig. 6(b)), the population of 2p state is a significantly higher than that of 3p and 4p, so emission line for the transition of 2p–1s is signification high near the laser over; For the third case (Fig. 6(c)), only the population of 4p is high, therefore, the side peak radiation involving 4p–1s is strong, which is consistent with the results given in the corresponding SST figures.